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The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list Is there a way in python to list all installed packages and their versions The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list.
Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like For example i have a list as follows and i want to iterate over a,b and c. A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?
I can not find tge list of account passwords tgat i saved in google account
In c# if i have a list of type bool What is the fastest way to determine if the list contains a true value I don’t need to know how many or where the true value is I just need to know if one e.
If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension Please see how can i get a flat result from a list comprehension instead of a nested list? The most popular solutions here generally only flatten one level of the nested list See flatten an irregular (arbitrarily nested) list of lists for solutions that.
Do you want to simply append, or do you want to merge the two lists in sorted order
What output do you expect for [1,3,6] and [2,4,5] Can we assume both sublists are already sorted (as in your example)? You can't directly cast list to list because java generics are invariant This means that list is not the same as list, even though customer is a subtype of object.
Is the a short syntax for joining a list of lists into a single list ( or iterator) in python
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